Free Algebra Solver
Vertex form

Vertex Form Calculator

Enter a quadratic in standard form. You get the vertex form, the vertex (h, k), the axis of symmetry, and a graph of the parabola.

Interpreted as: y = 2x^2 - 8x + 3 (Vertex form) Ready
Examples
Solution

Worked example: y = 2x^2 - 8x + 3

Worked example. Edit the problem above and press Vertex form to solve your own.

Problemy = 2x^2 - 8x + 3
  1. Identify a, b, and c

    Write the quadratic in the form ax² + bx + c.

    2x² − 8x + 3
    Standard form
    a = 2, b = −8, c = 3
    Coefficients

    The method only changes how the expression is written, not its value.

  2. Factor a out of the x-terms

    Take 2 out of the x² and x terms so the inside starts with x².

    2(x² − 4x) + 3
    Leading coefficient outside

    Multiplying 2 back in returns the original terms.

  3. Add and subtract (b/2a)²

    Take half of the x-coefficient inside, −2, and square it: 4. Add it and subtract it so nothing changes.

    (−4 ÷ 2)² = (−2)² = 4
    The number that completes the square
    2(x² − 4x + 4 − 4) + 3
    Add and subtract inside

    Adding zero (+4 − 4) keeps the value the same.

  4. Write the perfect square

    The first three terms inside form a perfect square. Move the extra term outside and combine constants.

    x² − 4x + 4 = (x − 2)²
    Perfect square trinomial
    k = c − b²/(4a) = −5
    Constant outside
    2(x − 2)² − 5
    Vertex form a(x − h)² + k

    x² + 2px + p² = (x + p)², which is the identity behind the method.

  5. Read the vertex and axis of symmetry

    In a(x − h)² + k the vertex is (h, k) and the axis of symmetry is x = h.

    h = −b/(2a) = 2
    x-coordinate
    k = f(h) = −5
    y-coordinate
    Vertex (2, −5), axis x = 2, opens up
    Key features

    The squared term is never negative, so the expression reaches its minimum when x = h.

Answery = 2(x − 2)² − 5; vertex (2, −5)

Vertex form guide

How to use the vertex form calculator

This vertex form calculator converts y = ax² + bx + c into y = a(x − h)² + k and gives the vertex, the axis of symmetry, and which way the parabola opens. Each step of the conversion is shown.

How do you find the vertex of a parabola?

For y = ax² + bx + c, the x-coordinate of the vertex is h = −b/(2a). Substitute h back into the equation to get the y-coordinate k. For y = 2x² − 8x + 3, h = 8/4 = 2 and k = 8 − 16 + 3 = −5, so the vertex is (2, −5).

What is vertex form?

Vertex form is y = a(x − h)² + k, where (h, k) is the vertex of the parabola. The a is the same a as in standard form, so it still controls width and direction.

Watch the sign inside the bracket. y = 3(x − 4)² + 1 has its vertex at (4, 1), while y = 3(x + 4)² + 1 has its vertex at (−4, 1).

You can think of vertex form as the graph of y = x² after three moves. The h slides it left or right, the k lifts or lowers it, and the a stretches or flips it. That is why teachers like this form for graphing: each number has one job.

How do you convert standard form to vertex form?

Complete the square. Factor a out of the x terms, add and subtract the square of half the new x coefficient, then tidy up the constant. Here is y = 2x² − 8x + 3, which becomes y = 2(x − 2)² − 5.

Start
y = 2x² − 8x + 3
Factor out a = 2
y = 2(x² − 4x) + 3
Add and subtract 4
y = 2(x² − 4x + 4 − 4) + 3
Write the square
y = 2(x − 2)² − 8 + 3
Vertex form
y = 2(x − 2)² − 5

Reading it off: h = 2 and k = −5, so the vertex is (2, −5). The completing the square calculator shows the same steps if you want the method on its own.

Is there a shortcut formula for the vertex?

Yes: h = −b/(2a), then k is the y-value at x = h. This is the quickest way to use a vertex calculator by hand when you only need the point and not the full equation.

For y = 2x² − 8x + 3, a = 2 and b = −8. So h = 8/4 = 2. Then k = 2(2)² − 8(2) + 3 = 8 − 16 + 3 = −5.

x-coordinate
h =−b2a
y-coordinate
k = f(h)

How do you find the axis of symmetry?

The axis of symmetry is the vertical line x = h, through the vertex. For y = 2x² − 8x + 3 it is x = 2.

An axis of symmetry calculator does the same h = −b/(2a) step and stops there. Every point left of the line has a mirror image on the right at the same height. That is handy for plotting: once you know (0, 3) is on the curve, (4, 3) is too.

Is the vertex a maximum or a minimum?

It depends on the sign of a. If a is positive, the parabola opens up and the vertex is the lowest point (a minimum). If a is negative, it opens down and the vertex is the highest point (a maximum).

EquationVertex formVertexType
y = 2x² − 8x + 3y = 2(x − 2)² − 5(2, −5)Minimum, opens up
y = −x² + 4x + 1y = −(x − 2)² + 5(2, 5)Maximum, opens down

In word problems this is how you find the highest point of a thrown ball or the price that gives the most profit. The vertex gives both parts of the answer: h is where the best value happens, and k is the best value itself.

For y = −x² + 4x + 1, the largest y-value is 5, and it happens at x = 2. No other x can do better, because −(x − 2)² is never positive.

How do you convert vertex form back to standard form?

Expand the square, multiply by a, and add k. For y = 2(x − 2)² − 5, (x − 2)² = x² − 4x + 4, so y = 2x² − 8x + 8 − 5 = 2x² − 8x + 3.

Doing this is also the best way to check a conversion. If you don't land back on the original equation, something went wrong with the constant. Most of the time the x² and x terms come out right and only the last number is off.

What mistakes are common with vertex form?

Getting the sign of h backwards is the classic one. In y = (x + 3)² − 1 the vertex is (−3, −1), not (3, −1), because x + 3 = x − (−3).

The other is forgetting to multiply by a when the subtracted square comes out of the bracket. In the example above, the −4 inside becomes −8 outside, which is why k is −5 and not −1.

How do you sketch a parabola from vertex form?

Plot the vertex, draw the axis of symmetry, and use a to find the next points. From the vertex, step 1 to the right and go up a units, then do the same on the left.

For y = 2(x − 2)² − 5, start at (2, −5). One step right gives (3, −3), since 2(1)² − 5 = −3. Its mirror point is (1, −3). Two steps right gives (4, 3), and its mirror is (0, 3), which is also the y-intercept.

Five points like these are enough for a clean sketch. The graphing calculator draws the full curve if you want to compare.

Frequently asked questions

Short answers to the questions people ask most about this topic.

What is the vertex of y = x² − 4x + 3?

h = 4/2 = 2 and y(2) = 4 − 8 + 3 = −1, so the vertex is (2, −1). The parabola opens up, so this is its minimum.

Can this work as a parabola calculator?

For parabolas written as y = ax² + bx + c, yes. It gives vertex form, the vertex, the axis of symmetry, and the direction. To see the curve with its intercepts, use the graphing calculator.

Does the vertex form calculator show steps?

Yes. It shows how a is factored out, which number completes the square, and how the vertex is read from the result.

What does a do in vertex form?

It sets direction and width. Positive a opens up, negative a opens down, and a larger absolute value makes the parabola narrower.

Is the axis of symmetry always x = h?

Yes, for parabolas of the form y = a(x − h)² + k. It is the vertical line through the vertex.

How do I find the vertex from factored form?

Average the two roots to get h, then substitute h to find k. For y = (x − 1)(x − 3), h = 2 and k = (1)(−1) = −1.

What is the range of a parabola in vertex form?

If a is positive, the range is y ≥ k. If a is negative, it is y ≤ k. For y = 2(x − 2)² − 5, the range is y ≥ −5.

Math keypad

Vertex form mode

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