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Synthetic division

Synthetic Division Calculator

Enter (polynomial) / (x − c). The calculator builds the synthetic division table, then reads off the quotient and remainder.

Interpreted as: (x^3 - 2x^2 - 4) / (x - 3) (Synthetic division) Ready
Examples
Solution

Worked example: (x^3 - 2x^2 - 4) / (x - 3)

Worked example. Edit the problem above and press Synthetic division to solve your own.

Problem(x^3 - 2x^2 - 4) / (x - 3)
  1. Write both polynomials in descending order

    Order the powers from highest to lowest and use 0 for any missing power.

    Dividend: x^3 − 2x^2 + 0x − 4
    Include every power
    Divisor: x − 3
    Divisor

    Placeholder zeros keep each power in its own column.

  2. Find the number for the synthetic division box

    Set the divisor equal to zero and solve. That value goes in the box.

    x − 3 = 0 → x = 3
    Use this number in the box

    Dividing by x − r is the same as using r in synthetic division.

  3. Bring down, multiply, and add

    Bring the first coefficient straight down. Multiply it by 3, write the product under the next coefficient, add, and repeat.

    3 │ 1 −2 0 −4
    Write the coefficients
    1 × 3 = 3; −2 + 3 = 1
    Multiply, then add down
    1 × 3 = 3; 0 + 3 = 3
    Multiply, then add down
    3 × 3 = 9; −4 + 9 = 5
    Multiply, then add down
    Bottom row: 1 1 3 5
    Last number is the remainder

    Each bottom-row number is a coefficient of the quotient, one degree lower than the dividend.

  4. Check: divisor × quotient + remainder

    Multiply the divisor by the quotient and add the remainder. You should get the dividend back.

    (x − 3)(x² + x + 3) + (5)
    Rebuild the dividend
    x³ − 2x² − 4
    Matches the dividend, so it checks out
    (x³ − 2x² − 4)/(x − 3) = x² + x + 3 + (5)/(x − 3)
    Final form

    This is the division algorithm: dividend = divisor × quotient + remainder.

AnswerQuotient: x² + x + 3; Remainder: 5

Synthetic division guide

How the synthetic division calculator works

The synthetic division calculator divides a polynomial by a linear factor using only the coefficients. Below you will see how to do synthetic division by hand, what the box number means, and when you should switch to long division.

How do you do synthetic division?

To do synthetic division by x − c, write c in the box and the coefficients of the dividend in a row, with 0 for any missing power. Bring down the first coefficient, multiply it by c, add the product to the next coefficient, and repeat. The last number is the remainder, and the others are the quotient.

What does a synthetic division calculator do?

A synthetic division calculator runs a shortcut for dividing a polynomial by a linear factor such as x − 3. It drops the variables and works only with numbers, so there is less to write and fewer signs to track.

It gives the same quotient and remainder as polynomial long division. The trade-off is that it only works when the divisor has degree 1.

What number goes in the box?

The box holds the root of the divisor. Set the divisor equal to 0 and solve: for x − 3 the box number is 3, and for x + 2 it is −2.

This is where sign errors start. The box number has the opposite sign of the number in the divisor, because x + 2 is the same as x − (−2). For a divisor like 2x − 1, solve 2x − 1 = 0 to get a box number of 1/2.

Synthetic division steps with an example

Here is (x³ − 2x² − 4) ÷ (x − 3). The dividend has no x term, so its coefficients are 1, −2, 0, −4. The box number is 3.

  1. Bring down the 1.
  2. Multiply 1 × 3 = 3 and add to −2 to get 1.
  3. Multiply 1 × 3 = 3 and add to 0 to get 3.
  4. Multiply 3 × 3 = 9 and add to −4 to get 5.
  5. Read the bottom row 1, 1, 3, 5. The last number, 5, is the remainder.
Row
3 | 1 −2 0 −4
Bottom row
1 1 3 5
Answer
x² + x + 3, remainder 5

The quotient starts one degree lower than the dividend. A cubic divided by a linear factor gives a quadratic, so 1, 1, 3 means x² + x + 3.

What does the remainder theorem say?

The remainder theorem says that when you divide P(x) by x − c, the remainder equals P(c). So synthetic division doubles as a fast way to evaluate a polynomial.

Check it with the example. P(3) = 27 − 18 − 4 = 5, which is the remainder from above. When the remainder is 0, c is a root and x − c is a factor. That is why the zeros calculator uses synthetic division to test candidates.

How do you use synthetic division with a divisor like 2x − 1?

Use the root 1/2 as the box number, run synthetic division as usual, then divide the quotient row by the leading coefficient 2. The remainder stays as it is.

For (2x³ − 3x² + 4x − 5) ÷ (2x − 1), the row 1/2 | 2, −3, 4, −5 gives the bottom row 2, −2, 3, −7/2. Dividing 2, −2, 3 by 2 gives the quotient x² − x + 3/2, and the remainder is −7/2.

This is the answer the calculator gives, and long division produces the same result. The extra division step is needed because dividing by x − 1/2 and dividing by 2x − 1 differ by a factor of 2.

Bottom row
2 −2 3 −7/2
Divide quotient by 2
x² − x + 3/2
Remainder
−7/2

How do you use synthetic division to factor a polynomial?

Find one root, divide it out with synthetic division, and factor the smaller quotient. Each zero remainder peels off one linear factor.

For x³ − 6x² + 11x − 6, try the box number 1. The row 1 | 1, −6, 11, −6 gives the bottom row 1, −5, 6, 0. The remainder is 0, so x − 1 is a factor and the quotient is x² − 5x + 6. That quadratic factors as (x − 2)(x − 3).

Row
1 | 1 −6 11 −6
Bottom row
1 −5 6 0
Factored
(x − 1)(x − 2)(x − 3)

You could start with 2 instead. Dividing by x − 2 gives x² − 4x + 3 with remainder 0, which factors as (x − 1)(x − 3). Any root leads to the same final answer.

When should you use long division instead?

Use long division whenever the divisor is quadratic or higher, such as x² + 1. Synthetic division has only one box number, so it cannot handle a divisor with two roots.

If you enter a divisor like x² + 1 here, the calculator will point you to the polynomial long division calculator. For any linear divisor, synthetic division is the faster choice.

What are the most common synthetic division mistakes?

Using the wrong sign in the box is the classic one. For x + 2, the box number is −2. Leaving out a 0 for a missing power is next: for x³ − 2x² − 4, the row needs 1, −2, 0, −4, not 1, −2, −4.

Some students also subtract instead of add. In synthetic division you always add down the columns, because the sign change is already built into the box number.

Frequently asked questions

Short answers to the questions people ask most about this topic.

How do I enter a problem in the synthetic division calculator?

Type it as (x^3 - 2x^2 - 4) / (x - 3). The calculator finds the box number, fills in placeholder zeros, and shows each multiply and add step.

Is synthetic division the same as long division?

It gives the same quotient and remainder for a linear divisor. It is shorter because it uses only the coefficients, but it does not work for divisors of degree 2 or higher.

What does a remainder of 0 mean?

It means the divisor is a factor and the box number is a root of the polynomial. For example, dividing x³ − 1 by x − 1 leaves 0, so x = 1 is a root.

How do I do synthetic division with x + 2?

Use −2 as the box number. For (x³ + 2x² − x + 5) ÷ (x + 2), the bottom row is 1, 0, −1, 7, so the quotient is x² − 1 and the remainder is 7.

Can synthetic division divide by 2x − 1?

Yes. Use 1/2 as the box number, then divide the quotient coefficients by 2. The remainder does not change.

Why is the quotient one degree lower?

Dividing by a degree 1 factor lowers the degree by one. A cubic dividend gives a quadratic quotient, a quartic gives a cubic, and so on.

Does synthetic division work with negative or fraction coefficients?

Yes. The bring down, multiply, add pattern works with any numbers. Negative coefficients just need care with signs, and fractions are added the usual way. The calculator keeps fractions exact, so a remainder like −7/2 is shown as a fraction rather than a decimal.

What should I write as my final answer?

Write the quotient plus the remainder over the divisor. For (x³ − 2x² − 4) ÷ (x − 3) that is x² + x + 3 + 5/(x − 3). If the remainder is 0, the quotient alone is the answer.

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Synthetic division mode

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